(5/4)a^2+62a+672=0

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Solution for (5/4)a^2+62a+672=0 equation: 



(5/4)a^2+62a+672=0



Domain of the equation: 4)a^2!=0

a!=0/1

a!=0

a∈R



We add all the numbers together, and all the variables

(+5/4)a^2+62a+672=0

We add all the numbers together, and all the variables

62a+(+5/4)a^2+672=0

We multiply all the terms by the denominator


62a*4)a^2+(+672*4)a^2+5=0

We add all the numbers together, and all the variables

62a*4)a^2+2688a^2+5=0

Wy multiply elements

248a^2=0

a = 248; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·248·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{496}=0$

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